(1)/(4x^2-25)+(6)/(2x+5)

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Solution for (1)/(4x^2-25)+(6)/(2x+5) equation:


D( x )

2*x+5 = 0

4*x^2-25 = 0

2*x+5 = 0

2*x+5 = 0

2*x+5 = 0 // - 5

2*x = -5 // : 2

x = -5/2

4*x^2-25 = 0

4*x^2-25 = 0

4*x^2 = 25 // : 4

x^2 = 25/4

x^2 = 25/4 // ^ 1/2

abs(x) = 5/2

x = 5/2 or x = -5/2

x in (-oo:-5/2) U (-5/2:5/2) U (5/2:+oo)

1/(4*x^2-25)+6/(2*x+5) = 0

(1*(2*x+5))/((4*x^2-25)*(2*x+5))+(6*(4*x^2-25))/((4*x^2-25)*(2*x+5)) = 0

1*(2*x+5)+6*(4*x^2-25) = 0

24*x^2+2*x-145 = 0

24*x^2+2*x-145 = 0

24*x^2+2*x-145 = 0

DELTA = 2^2-(-145*4*24)

DELTA = 13924

DELTA > 0

x = (13924^(1/2)-2)/(2*24) or x = (-13924^(1/2)-2)/(2*24)

x = 29/12 or x = -5/2

(x+5/2)*(x-29/12) = 0

((x+5/2)*(x-29/12))/((4*x^2-25)*(2*x+5)) = 0

((x+5/2)*(x-29/12))/((4*x^2-25)*(2*x+5)) = 0 // * (4*x^2-25)*(2*x+5)

(x+5/2)*(x-29/12) = 0

( x+5/2 )

x+5/2 = 0 // - 5/2

x = -5/2

( x-29/12 )

x-29/12 = 0 // + 29/12

x = 29/12

x in { -5/2}

x = 29/12

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